AP Math Revision › High school math › Algebra 1 › Unit 6
Algebra 1 Unit 6: Polynomials and Factoring
Adding, subtracting and multiplying polynomials, and factoring by common factor, trinomials, special products and grouping. 12 questions. Have a go at each one on paper before you tap "Show me how".
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Question 1
Adding and subtracting polynomialsNo calculatorSimplify $(3x^2-5x+2)-(x^2+4x-7)$.
- $2x^{2}-9x-5$
- $4x^{2}-x-5$
- $2x^{2}-9x+9$
- $2x^{2}-x-5$
Question 2
Multiplying polynomialsNo calculatorMultiply $(2x-3)(x+5)$.
- $2x^{2}+13x-15$
- $2x^{2}-7x-15$
- $2x^{2}-15$
- $2x^{2}+7x-15$
Question 3
Multiplying polynomialsNo calculatorExpand $(x-4)^2$.
- $x^{2}-16$
- $x^{2}+16$
- $x^{2}-4x+16$
- $x^{2}-8x+16$
Question 4
Factoring trinomialsNo calculatorFactor $x^2+2x-24$.
- $(x+6)(x-4)$
- $(x-6)(x+4)$
- $(x-8)(x+3)$
- $(x+8)(x-3)$
Question 5
Factoring trinomialsNo calculatorFactor $2x^2+7x+3$.
- $(2x+1)(x+3)$
- $(x+1)(x+3)$
- $(2x-1)(x-3)$
- $(2x+3)(x+1)$
Question 6
Special productsNo calculatorFactor $9x^2-49$.
- $(3x+7)^{2}$
- $(3x-7)^{2}$
- $(3x-7)(3x+7)$
- $(9x-7)(x+7)$
Question 7
Greatest common factorNo calculatorFactor out the greatest common factor: $6x^3-15x^2$.
- $3x^{2}(2x-5)$
- $3x(2x^{2}-5x)$
- $3x^{2}(2x+5)$
- $x^{2}(6x-15)$
Question 8
Polynomial vocabularyNo calculatorWhat are the degree and the leading coefficient of $4x^3-2x^5+x-7$?
- Degree 5, leading coefficient 2
- Degree 3, leading coefficient 4
- Degree 5, leading coefficient -2
- Degree 4, leading coefficient -7
Question 9
Factoring completelyNo calculatorFactor completely: $2x^2-18$.
- $2(x-3)^{2}$
- $(2x-6)(x+3)$
- $2(x-3)(x+3)$
- $2(x^{2}-9)$
Question 10
Factoring by groupingNo calculatorFactor completely: $x^3+3x^2-4x-12$.
- $(x+3)(x-2)(x+2)$
- $(x+3)(x^{2}-4)$
- $(x-3)(x-2)(x+2)$
- $(x+3)(x-4)(x+1)$
Question 11
Multiplying polynomialsNo calculatorA rectangle has length $3x+2$ and width $x-4$. Which expression gives its area?
- $3x^{2}-14x-8$
- $4x-2$
- $8x-4$
- $3x^{2}-10x-8$
Question 12
Zero product propertyNo calculatorSolve $(2x-5)(x+3)=0$.
- $x=\frac{2}{5} \text{ or } x=-3$
- $x=5 \text{ or } x=-3$
- $x=\frac{5}{2} \text{ or } x=-3$
- $x=-\frac{5}{2} \text{ or } x=3$
Common Core: A-APR.A.1, A-SSE.A.2, A-SSE.B.3.
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